here is the introduce:
For bodystyle molecule, each set of atoms in the fix group with a different molecule ID is treated as a rigid body.
if one atom is not glued to the other, i mean ,maybe far away from each other,i assign different molecule id for the two atoms .Do the command treat the two atoms as a rigid body?
here is the introduce:
For bodystyle molecule, each set of atoms in the fix group with a different
molecule ID is treated as a rigid body.if one atom is not glued to the other, i mean ,maybe far away from each
other,i assign different molecule id for the two atoms .Do the command treat
the two atoms as a rigid body?
no.
here is the introduce:
For bodystyle molecule, each set of atoms in the fix group with a different
molecule ID is treated as a rigid body.
perhaps this sentence is more easily understood if reformulated like this:
For bodystyle {molecule}, each set of atoms in the fix group with the
same molecule ID is treated as a different rigid body.
or with a little more detail:
For bodystyle {molecule} atoms are grouped into rigid bodies by their
molecule ID, i.e. each set of atoms in the fix group with the same
molecule ID is treated as a different rigid body.
like this,all of the atoms are attach to each other,the number is molecule id .Will the command treat these atoms as eight rigid bodies?
just like this?
like this,all of the atoms are attach to each other,the number is molecule
id .Will the command treat these atoms as eight rigid bodies?just like
this?
no. you have two molecule IDs, so there will be two rigid objects.
axel.
Thanks!I thought the command treat atoms as a rigid body with different molecule id at first!
Thanks!I thought the command treat atoms as a rigid body with different
molecule id at first!
it said *sets* of atoms. also, it doesn't make sense to combine different
molecule ids into one rigid objects: how would LAMMPS be able to tell,
which goes with which?
i will propose to have my reformulated expression used in the manual to
reduce confusion.
axel.