cna for fcc with Pd in vacuum

Hello, today i trate to make an analysis by cna for a solid of palladium with 2000 atoms in vacuum, i want understand the result, because he doesn’t show me a entire, how 1 for a fcc, he show me a 0.0043252595 and i don’t know what does mean. If somebody can help me, i would grateful.

I suggest reading the compute cna/atom doc page
carefully as well as the CNA papers cited there. The
compute should be calculating values consistent with
those papers.

Steve