compute displace/atom

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1

Dear All,
I am using LAMMPS (14 Feb 2014) and have some questions about compute displace/atom :
manual tells me :

IMPORTANT NOTE: Initial coordinates are stored in “unwrapped” form, by using the image flags associated
with each atom.
Does it mean that displacements of all the atoms passing thru a periodic boundary one or more timesare are output in “unwrapped” coordinates form?

Thank you very much for your answer

2

yes - displacement is the difference between
two unwrapped coords. The value is not
itself “wrapped” to yield a value less than the box
length.

Steve