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Q: What is the sum of two even consecutive integers the equal 100?

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The integers are 99, 100 and 101. There is also a set of consecutive even integers whose sum is 300. That set is 98, 100 and 102.

101

None exist. 100 is an even number and two consecutive integers can only add up to an odd number. This is because only 2 evens can add up to an even number and no two even numbers are consecutive. (or two odds, but no two odd numbers are consecutive either)

They are 2n+2

The GCF of consecutive integers is 1.

The average of the three integers is going to be -306/3 = -102. Therefore, taking one even integer from either side, -306 = (-100) + (-102) + (-104)

49, 51

99, 100, and 101

All of them from 45 to 99 ... 55 integers.

100

100

49 and 51

There are 80 such integers.

48

10100.

2550

Call the unknown higher integer h. Then, from the problem statement, 4h + (h-2) = 98; 5h = 100; h = 20. Thus the two integers are 18 and 20.

The sum of such numbers is 504.

99, 100, and 101

Alpha is the significance level of the test and has little to do with the failure rate of parts (or even parst!).

50%

A century equals 100 consecutive years. That means: 7 centuries equal 700 consecutive years.

98, 100, 102

96+98+100 = 294