dpd-SSA example

Dear LAMMPS users,

Can anyone please suggest that how to calculate configuration energy of dpd fluid in LAMMPS. Is configurational energy and potential energy is the same thing?
I am trying to calculate configurational energy by modifying dpd SSA example in LAMMPS June 2016 version (in UNBUNTU) for isthothermal conditions. Following is the input file

Input File for DPD fluid under isothermal conditions using the VV-SSA integration scheme

log log.dpd-lj7
boundary p p p

units lj
atom_style dpd # Can be either dpd or atomic
region 1 block 0 15 0 15 0 15 units box
create_box 1 1
create_atoms 1 random 10125 2222 NULL

comm_modify mode single vel yes
mass 1 1

pair_style dpd/fdt 1 2.5 234324
pair_coeff 1 1 62.5 3 2.5

neighbor 0.2 bin
neigh_modify every 1 delay 0 check no once no

timestep 0.01

thermo 100

thermo_style custom step temp press pe ke etotal
thermo_modify format float %15.10f

fix 1 all shardlow
fix 2 all nve

run 5000

I took the parameters from the following paper
Dissipative particle dynamics at isothermal, isobaric, isoenergetic, and isoenthalpic conditions using Shardlow-like splitting algorithms.

Thanks

Dear LAMMPS users,

Can anyone please suggest that how to calculate configuration energy of
dpd fluid in LAMMPS. Is configurational energy and potential energy is the
same thing?
I am trying to calculate configurational energy by modifying dpd SSA
example in LAMMPS June 2016 version (in UNBUNTU) for isthothermal
conditions. Following is the input file

​you'll be best off contacting the USER-DPD package developers directly
(see the docs and the README file in the src/USER-DPD folder. since this
package has seen many updates and improvements since 2016, i also strongly
recommend to update to the latest LAMMPS version (latest stable release is
currently 11Aug2017​, very latest patch is 1Sep2017).

​axel.​